The cleavage step of the reaction involves a covalent bond between Tyr 319 and the 5'-phosphoryl end of the broken strand. The 3' end of the broken DNA strand is likely to remain associated with either domain I or IV. A proton is removed from the tyrosyl hydroxyl in the formation of the phosphotyrosine bond, and a proton is added to the deoxyribose 3' oxygen as it departs from the scissile phosphate. When the DNA rejoins the steps are reversed. Glu-9 is thought to be the best candidate for both the proton donor and acceptor (Chen, 1998).
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Updated: December 11, 1998
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